1/2(8a^2-10a+7)

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Solution for 1/2(8a^2-10a+7) equation:


a in (-oo:+oo)

(1/2)*(8*a^2-(10*a)+7) = 0

(1/2)*(8*a^2-10*a+7) = 0

1/2*(8*a^2-10*a+7) = 0

8*a^2-10*a+7 = 0

8*a^2-10*a+7 = 0

DELTA = (-10)^2-(4*7*8)

DELTA = -124

DELTA < 0

1 = 0

1/2 = 0

a belongs to the empty set

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